Answer
$$s=\frac{-3+\sqrt{13}}{2},\:s=\frac{-3-\sqrt{13}}{2}$$
Work Step by Step
The quadratic formula states:
$$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
Thus, solving the equation, we find:
$$ s_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\left(-1\right)}}{2\cdot \:1} \\ s=\frac{-3+\sqrt{13}}{2},\:s=\frac{-3-\sqrt{13}}{2}$$