Answer
$$k=-\frac{1}{3},\:k=-\frac{3}{2}$$
Work Step by Step
The quadratic formula states:
$$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
Thus, solving the equation, we find:
$$ k_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:6\cdot \:3}}{2\cdot \:6} \\ k=-\frac{1}{3},\:k=-\frac{3}{2}$$
