Answer
$$3\left(t+4\right)^2-61$$
Work Step by Step
Completing the square, we obtain:
$$ 3\left(t^2+8t-\frac{13}{3}+4^2-4^2\right) \\ 3\left(\left(t+4\right)^2-\frac{13}{3}-4^2\right) \\ 3\left(t+4\right)^2-61$$
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