Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - Exercises for Skills for Completing the Square - Page 138: 40

Answer

$$v=2+\sqrt{13},\:v=2-\sqrt{13}$$

Work Step by Step

The quadratic formula states: $$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ Thus, solving the equation, we find: $$ v_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\left(-9\right)}}{2\cdot \:1} \\ v=2+\sqrt{13},\:v=2-\sqrt{13}$$
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