Answer
$1$
Work Step by Step
Solve $\int_{\ln (2)}^{\ln (3)} e^x dx$
This implies $\int_{\ln (2)}^{\ln (3)} e^x dx=[e^x]_{\ln (2)}^{\ln (3)}$
Thus, $\int_{\ln (2)}^{\ln (3)} e^x dx=[e^{ln (3)}-e^{ln (2)}]$
or, $\int_{\ln (2)}^{\ln (3)} e^x dx=3-2$
Hence, $\int_{\ln (2)}^{\ln (3)} e^x dx=1$
