Answer
$8 e^{x+1} +c$
Work Step by Step
Solve $\int 8 e^{x+1} dx$
Let us $p= x+1$ and $dp=dx$
This implies $\int 8 e^{x+1} dx= 8 \int e^p dp$
$= 8 e^p+c$
$= 8 e^{x+1} +c$
Hence, $\int 8 e^{x+1} dx=8 e^{x+1} +c$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 7 - Section 7.1 - The Logarithm Defined as an Integral - Exercises - Page 401: 10
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