University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Section 7.1 - The Logarithm Defined as an Integral - Exercises - Page 401: 10


$8 e^{x+1} +c$

Work Step by Step

Solve $\int 8 e^{x+1} dx$ Let us $p= x+1$ and $dp=dx$ This implies $\int 8 e^{x+1} dx= 8 \int e^p dp$ $= 8 e^p+c$ $= 8 e^{x+1} +c$ Hence, $\int 8 e^{x+1} dx=8 e^{x+1} +c$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.