Answer
$$\int^{3}_{0}(\sqrt 2+1)x^{\sqrt2}dx=3^{\sqrt2+1}$$
Work Step by Step
$$A=\int^{3}_{0}(\sqrt 2+1)x^{\sqrt2}dx$$ $$A=(\sqrt2+1)\frac{x^{\sqrt2+1}}{\sqrt2+1}\Big]^{3}_{0}$$ $$A=(x^{\sqrt2+1})\Big]^{3}_{0}$$ $$A=3^{\sqrt2+1}-0^{\sqrt2+1}$$ $$A=3^{\sqrt2+1}$$
