Answer
$2 e^{\sqrt r} +c$
Work Step by Step
Solve $\int e^{\sqrt r} \dfrac{1}{\sqrt r}dr$
Let us $p=\sqrt r$ and $dp=\dfrac{1}{2 \sqrt r}dr$
This implies $\int e^{\sqrt r} \dfrac{1}{\sqrt r}dr=2\int e^p dp $
$=2 e^{p} +c$
$=2 e^{\sqrt r} +c$
Hence, $\int e^{\sqrt r} \dfrac{1}{\sqrt r}dr=2 e^{\sqrt r} +c$