University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Section 7.1 - The Logarithm Defined as an Integral - Exercises - Page 401: 3


$\ln |y^2-25|+c$

Work Step by Step

Solve $\int\dfrac{2ydy}{y^2-25}$ Let $p=y^2-25$ and $dp=2ydy$ This implies $\int\dfrac{2ydy}{y^2-25}=\int\dfrac{dp}{p}=\ln|p|+c$ Since, $p=y^2-25$ Thus, $=\ln |y^2-25|+c$
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