University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 7 - Section 7.1 - The Logarithm Defined as an Integral - Exercises - Page 401: 3

Answer

$\ln |y^2-25|+c$

Work Step by Step

Solve $\int\dfrac{2ydy}{y^2-25}$ Let $p=y^2-25$ and $dp=2ydy$ This implies $\int\dfrac{2ydy}{y^2-25}=\int\dfrac{dp}{p}=\ln|p|+c$ Since, $p=y^2-25$ Thus, $=\ln |y^2-25|+c$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.