## University Calculus: Early Transcendentals (3rd Edition)

$\int_{-3}^{-2}\dfrac{dx}{x}=\ln(\dfrac{2}{3})$
Solve $\int_{-3}^{-2}\dfrac{dx}{x}$ $\int_{-3}^{-2}\dfrac{dx}{x}=[\ln |x|]_{-3}^{-2}$ This implies $[\ln |x|]_{-3}^{-2}=\ln |-2|-\ln |-3|$ $=\ln 2-\ln 3$ Use logarithmic properties, $\ln m-\ln n=\ln(\dfrac{m}{n})$, we have Hence, $\int_{-3}^{-2}\dfrac{dx}{x}=\ln(\dfrac{2}{3})$