Answer
$$y'=\frac{1-e}{t^e}$$
Work Step by Step
$$y=t^{1-e}$$
Recall the General Power Rule for Derivatives: $$\frac{d}{dt}t^n=nt^{n-1}$$
Apply here to find $y'$: $$y'=(t^{1-e})'=(1-e)t^{(1-e)-1}=(1-e)t^{-e}$$
$$y'=\frac{1-e}{t^e}$$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 3 - Section 3.8 - Derivatives of Inverse Functions and Logarithms - Exercises - Page 175: 72
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