University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.8 - Derivatives of Inverse Functions and Logarithms - Exercises - Page 175: 71

Answer

$$y'=\pi x^{\pi-1}$$

Work Step by Step

$$y=x^\pi$$ Recall the General Power Rule for Derivatives: $$\frac{d}{dx}x^n=nx^{n-1}$$ Apply here to find $y'$: $$y'=(x\pi)'=\pi x^{\pi-1}$$
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