Answer
$$y'=\frac{5^{\sqrt s}\ln5}{2\sqrt s}$$
Work Step by Step
$$y=5^{\sqrt s}$$
Recall Theorem 5: $$\frac{d}{ds}a^u=a^u\ln a\frac{du}{ds}$$
Apply here to find $y'$: $$y'=(5^{\sqrt s})'=5^{\sqrt s}\ln 5(\sqrt s)'=5^{\sqrt s}\ln 5\times\frac{1}{2\sqrt s}$$
$$y'=\frac{5^{\sqrt s}\ln5}{2\sqrt s}$$
