University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 3 - Section 3.8 - Derivatives of Inverse Functions and Logarithms - Exercises - Page 175: 19

Answer

$$y'=\frac{3}{x}$$

Work Step by Step

$$y=\ln(x^3)$$ Recall the following Derivative Rules: $$\frac{d}{dx}(\ln u)=\frac{1}{u}\frac{du}{dx}$$ Therefore, we have $$y'=\Big(\ln(x^3)\Big)'=\frac{1}{x^3}\times(x^3)'=\frac{3x^2}{x^3}$$ $$y'=\frac{3}{x}$$
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