Answer
$$y'=\frac{3}{x}$$
Work Step by Step
$$y=\ln(x^3)$$
Recall the following Derivative Rules: $$\frac{d}{dx}(\ln u)=\frac{1}{u}\frac{du}{dx}$$
Therefore, we have $$y'=\Big(\ln(x^3)\Big)'=\frac{1}{x^3}\times(x^3)'=\frac{3x^2}{x^3}$$
$$y'=\frac{3}{x}$$