Answer
$$y'=2^x\ln 2$$
Work Step by Step
$$y=2^x$$
Recall Theorem 5: $$\frac{d}{dx}a^u=a^u\ln a\frac{du}{dx}$$
Apply here to find $y'$: $$y'=(2^x)'=2^x\ln 2(x)'$$
$$y'=2^x\ln 2$$
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