Answer
$$\lim_{x\to0}\frac{4}{x^{2/5}}=\infty$$
Work Step by Step
$$A=\lim_{x\to0}\frac{4}{x^{2/5}}=\lim_{x\to0}\frac{4}{\sqrt[5]{x^2}}$$
As $x\to0$, $\sqrt[5]{x^2}$ approaches $0$ as well.
Since $x^2\gt0$ for all $x$, $\sqrt[5]{x^2}\gt0$ also for all $x$, so $4/\sqrt[5]{x^{2}}$ will approach $\infty$. Therefore,
$$A=\infty$$
