Answer
$$\lim_{x\to2^-}\frac{3}{x-2}=-\infty$$
Work Step by Step
$$A=\lim_{x\to2^-}\frac{3}{x-2}$$
As $x\to2^-$, $x-2$ approaches $0$ from the left, where $(x-2)\lt 0$, so $3/(x-2)$ will approach $-\infty$. Therefore,
$$A=\lim_{x\to2^-}\frac{3}{x-2}=-\infty$$
