University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.6 - Limits Involving Infinity; Asymptotes of Graphs - Exercises - Page 108: 38



Work Step by Step

$$A=\lim_{x\to0^-}\frac{5}{2x}$$ As $x\to0^-$, $2x$ approaches $0$ from the left, where $2x\lt 0$, so $5/2x$ will approach $-\infty$. Therefore, $$A=\lim_{x\to0^-}\frac{5}{2x}=-\infty$$
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