Answer
$$\lim_{x\to7}\frac{4}{(x-7)^2}=\infty$$
Work Step by Step
$$A=\lim_{x\to7}\frac{4}{(x-7)^2}$$
As $x\to7$, $x-7$ approaches $0$ and $(x-7)^2$ approaches $0$ as well.
Since $(x-7)^2\ge0$ for all $x$, $4/(x-7)^2$ will approach $\infty$. Therefore,
$$A=\infty$$
