University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 14 - Practice Exercises - Page 817: 26

Answer

$1$

Work Step by Step

Consider $I=\int_{1}^{e} \int_{1}^{x} \int_{0}^{z} (\dfrac{2y}{z^3}) \ dy \ dz \ dx$ or, $=\int_{1}^{e} \int_{1}^{x} \dfrac{1}{z} \ dz \ dx$ or, $=\int_{1}^{e} [\ln (x)] \ dx$ or, $=[ x \ln x -x]_1^e$ or, $=[x(\ln x-1)]_1^e$ or, $=(e-1)[(\ln e-\ln 1)-1]$ or, $=1$
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