Answer
$e-1$
Work Step by Step
Consider $I=\int_{0}^{2} \int_{y/2}^{1} e^{x^2} \ dx \ dy$
or, $=\int_{0}^{1} \int_{0}^{2x} e^{ x^2} \ dy \ dx$
or, $=\int_{0}^{1} 2x e^{x^2} \ dx$
or, $=[e^{x^2}]_0^1$
or, $=e^{1}-e^0$
or, $=e-1$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 14 - Practice Exercises - Page 817: 10
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