University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.5 - Exponential Functions - Exercises - Page 38: 14



Work Step by Step

$$\frac{3^{5/3}}{3^{2/3}}$$ As $3\gt0$, we can apply the law of exponents here. We would need to apply this law: $$\frac{a^x}{a^y}=a^{x-y}$$ Therefore, $$\frac{3^{5/3}}{3^{2/3}}=3^{(5/3-2/3)}=3^{3/3}=3^1=3$$
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