University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.5 - Exponential Functions - Exercises - Page 38: 11



Work Step by Step

$$16^2\times16^{-1.75}$$ As $16\gt0$, we can apply the law of exponents here, which states that $$a^x\times a^y=a^{x+y}$$ Therefore, $$16^2\times16^{-1.75}=16^{2-1.75}=16^{0.25}=16^{1/4}=\sqrt[4]{16}=2$$
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