## University Calculus: Early Transcendentals (3rd Edition)

$$16^2\times16^{-1.75}=2$$
$$16^2\times16^{-1.75}$$ As $16\gt0$, we can apply the law of exponents here, which states that $$a^x\times a^y=a^{x+y}$$ Therefore, $$16^2\times16^{-1.75}=16^{2-1.75}=16^{0.25}=16^{1/4}=\sqrt[4]{16}=2$$