University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.5 - Exponential Functions - Exercises - Page 38: 12



Work Step by Step

$$9^{1/3}\times9^{1/6}$$ As $9\gt0$, we can apply the law of exponents here. We would need to apply this law: $$a^x\times a^y=a^{x+y}$$ Therefore, $$9^{1/3}\times9^{1/6}=9^{1/3+1/6}=9^{1/2}=\sqrt9=3$$
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