Answer
$$\Big(\frac{\sqrt6}{3}\Big)^2=\frac{2}{3}$$
Work Step by Step
$$\Big(\frac{\sqrt6}{3}\Big)^2$$
As $\sqrt6\gt0$ and $3\gt0$, we can apply the law of exponents here.
Applying this law: $$\Big(\frac{a}{b}\Big)^x=\frac{a^x}{b^x}$$ we have
$$\Big(\frac{\sqrt6}{3}\Big)^2=\frac{(\sqrt6)^2}{3^2}=\frac{6}{9}=\frac{2}{3}$$
