University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.5 - Exponential Functions - Exercises - Page 38: 13



Work Step by Step

$$\frac{4^{4.2}}{4^{3.7}}$$ As $4\gt0$, we can apply the law of exponents here. We would need to apply this law: $$\frac{a^x}{a^y}=a^{x-y}$$ Therefore, $$\frac{4^{4.2}}{4^{3.7}}=4^{(4.2-3.7)}=4^{0.5}=\sqrt4=2$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.