## University Calculus: Early Transcendentals (3rd Edition)

$$\frac{4^{4.2}}{4^{3.7}}=2$$
$$\frac{4^{4.2}}{4^{3.7}}$$ As $4\gt0$, we can apply the law of exponents here. We would need to apply this law: $$\frac{a^x}{a^y}=a^{x-y}$$ Therefore, $$\frac{4^{4.2}}{4^{3.7}}=4^{(4.2-3.7)}=4^{0.5}=\sqrt4=2$$