University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 1 - Section 1.5 - Exponential Functions - Exercises - Page 38: 17



Work Step by Step

$$2^{\sqrt3}\times7^{\sqrt3}$$ As $2\gt0$ and $7\gt0$, we can apply the law of exponents here. Applying this law: $$a^x\times b^x=(ab)^x$$ we have $$2^{\sqrt3}\times7^{\sqrt3}=(2\times7)^{\sqrt3}=14^\sqrt3$$
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