Answer
$$\Big(\frac{2}{\sqrt2}\Big)^4=4$$
Work Step by Step
$$\Big(\frac{2}{\sqrt2}\Big)^4$$
As $2\gt0$ and $\sqrt{2}\gt0$, we can apply the law of exponents here.
Applying this law: $$\Big(\frac{a}{b}\Big)^x=\frac{a^x}{b^x}$$ we have
$$\Big(\frac{2}{\sqrt2}\Big)^4=\frac{2^4}{(\sqrt2)^4}=\frac{16}{4}=4$$
