Answer
=$2$
This is not a probability density.
Work Step by Step
$\int^\infty_0\frac{8}{\pi(4+x^2)}dx$
=$\lim\limits_{b \to \infty}[\frac{4}{\pi}\tan^-1(\frac{x}{2})]^b_0]$
=$\frac{4}{\pi}\frac{\pi}{2}$=$2$
This is not a probability density.
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 6
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