Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 12

Answer

=$0.599$

Work Step by Step

$\int^{15}_2\frac{\ln x}{x^2}dx$=$-\frac{\ln x+1}{x}]^{15}_2$ =$-\frac{\ln15}{15}-\frac{1}{15}+\frac{\ln2}{2}+\frac{1}{2}$=$0.599$
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