Answer
=$1$
This is a probability density
Work Step by Step
$\int^\frac{\ln(1+\ln2)}{\ln2}_02^xdx$
=$\frac{2^x}{\ln2}]^\frac{\ln(1+\ln2)}{\ln2}_0$
=$[\frac{1+\ln2}{\ln2}-\frac{1}{\ln2}]$=$1$
This is a probability density
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 3
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