Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 16

Answer

=$0.159$

Work Step by Step

$\int^\frac{\pi}{4}_\frac{\pi}{6} sinx dx$=$-cosx]^\frac {\pi}{4}_\frac{\pi}{6}$ =$-\frac{\sqrt 2}{2}+\frac{\sqrt 3}{2}$=$0.159$
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