Answer
$c$=$\sqrt {21}$
Work Step by Step
$\int^c_3\frac{1}{6}xdx$
=$\frac{1}{12}c^2-\frac{3}{4}$
solving $\frac{1}{12}c^2-\frac{3}{4}$
=$1$
we find $c$=$\sqrt {21}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 17
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