Answer
$c$=$\frac{1}{2}\ln2$
Work Step by Step
$\int^c_04e^{-2x}dx$
=$-2e^{-2c}+2$
By Solving
$-2e^{-2c}+2$=$1$,
We find
$c$=$\frac{1}{2}\ln2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 8: Techniques of Integration - Section 8.9 - Probability - Exercises 8.9 - Page 514: 19
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