Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Practice Exercises - Page 308: 70


Yes, see explanations.

Work Step by Step

Step 1. By definition, the average value of an integrable function $f(x)$ over an interval of $[a,b]$ can be written as $\bar f=av(f)=\frac{1}{b-a}\int_a^b f(x)dx$. Step 2. Given that the interval length is $2$, we have $b-a=2$ and $\bar f=av(f)=\frac{1}{2}\int_a^b f(x)dx$ which equals to half of the function's integral over the interval.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.