Answer
$y=\int_5^x (\frac{sin(u)}{u})du -3$
Work Step by Step
Step 1. Letting $f(x)=\frac{sin(x)}{x}$ and $F(x)=\int_a^x f(u)du+C$, we have $F'(x)=f(x)$ where $C$ is a constant.
Step 2. In the case of the exercise, we can write $y=\int_a^x f(u)du +C$, where $C$ is a constant.
Step 3. Given $y(5)=-3$, we have $f(5)=\int_a^5 f(u)du +C=-3$; thus we can let $a=5, C=-3$.
Step 4. The solution can be written as
$y=\int_5^x f(u)du -3$
