Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Practice Exercises - Page 308: 49

Answer

1

Work Step by Step

Rewrite the equation: $\int t^{-3/2}dt$ with limits from 1 to 4 Integrate with respect to t by taking the antiderivative of each term. Then plug in limits to evaluate: $=-2t^{-1/2}$ with limits from 1 to 4 $=-2[(4)^{-1/2}-(1)^{-1/2}]=-2(\frac{1}{2}-1)=-2(-1/2)=1$
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