Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 5: Integrals - Practice Exercises - Page 308: 48



Work Step by Step

Integrate with respect to x by taking the antiderivative of each term. Then plug in limits to evaluate: $=-3x^{-1/3}$ with limits from 1 to 27 $=-3[(27)^{-1/3}-(1)^{-1/3}]=3(\frac{1}{3}-1)=3(2/3)=2$
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