Thomas' Calculus 13th Edition

Integrate with respect to s by taking the antiderivative of each term. Then plug in limits to evaluate: $=\frac{8s^4}{4}-\frac{12s^3}{3}+5s=2s^4-4s^3+5s$ with limits from 0 to 1 $=[2(1)^4-4(1)^3+5(1)]-[2(0)^4-4(0)^3+5(0)]$ $=(2-4+5)-0=3$