Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 9



Work Step by Step

Take the derivative of the equation using the Quotient Rule. Then apply Chain Rule: $s'=\frac{(1+t^{1/2})(\frac{1}{2}t^{-1/2})-(t^{1/2})(\frac{1}{2}t^{-1/2})}{(1+t^{1/2})^2}$ $=\frac{\frac{1}{2}t^{-1/2}+\frac{1}{2}(1)-\frac{1}{2}(1)}{(1+t^{1/2})^2}$ $=\frac{1}{2t^{1/2}(1+t^{1/2})^2}$
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