Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 23



Work Step by Step

Take the derivative of the equation using Power Rule, Trigonometric derivatives, Product Rule, and Chain Rule: $y'=x^{-1/2}\times sec(2x)^2tan(2x)^2\times2(2x)\times2-\frac{1}{2}x^{-3/2}sec(2x)^2$ $=8x^{1/2}sec(2x)^2tan(2x)^2-\frac{1}{2}x^{-3/2}sec(2x)^2$
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