## Thomas' Calculus 13th Edition

$y'=(2x+2)(x+1)^2+(2x+2)(x^2+2x)$
Use the Power Rule to take the derivative of each term in the equation. First, keep the first term, and take the derivative of the second term, multiplying them together. Then add the second term multiplied with the derivative of the first term: $y'=(x+1)^2(2x+2)+2(x+1)(x^2+2x)$ $=(2x+2)(x+1)^2+(2x+2)(x^2+2x)$