Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 8

Answer

$y'=(-2-cscθ-\frac{θ^2}{2})\times(\frac{cscθcotθ}{2}-θ/2)$

Work Step by Step

Take the derivative of the equation using Trigonometric Derivatives and Power Rule. Then apply Chain Rule to the inner terms: $y'=2(-1-\frac{cscθ}{2}-\frac{θ^2}{4})\times(0+\frac{cscθcotθ}{2}-\frac{2θ}{4})$ $=(-2-cscθ-\frac{θ^2}{2})\times(\frac{cscθcotθ}{2}-θ/2)$
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