Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 21

Answer

$y'=csc(\frac{2}{x})cot(\frac{2}{x})+xcsc(\frac{2}{x})$

Work Step by Step

Take the derivative of the equation using Product Rule, Power Rule, and Trigonometric derivatives: $y'=\frac{1}{2}x^2\times-csc(\frac{2}{x})cot(\frac{2}{x})\times\frac{-2}{x^2}+xcsc(\frac{2}{x})$ $=csc(\frac{2}{x})cot(\frac{2}{x})+xcsc(\frac{2}{x})$
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