Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 17



Work Step by Step

Rewrite the equation: $r=(2θsinθ)^{1/2}$ Take the derivative the equation using a Trigonometric derivative and Chain Rule: $r'=\frac{1}{2}(2θsinθ)^{-1/2}\times(2θcosθ+2sinθ)$ $=\frac{2θcosθ+2sinθ}{2(2θsinθ)^{1/2}}$
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