Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Practice Exercises - Page 177: 15

Answer

$s'=5(sec(t)tan(t)+sec^2(t))(sec(t)+tan(t))^4$

Work Step by Step

Take the derivative of the equation using Trigonometric derivatives and Chain Rule: $s'=5\times(sec(t)+tan(t))^4\times(sec(t)tan(t)+sec^2(t))$ $=5(sec(t)tan(t)+sec^2(t))(sec(t)+tan(t))^4$
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