## Thomas' Calculus 13th Edition

$s'=5(sec(t)tan(t)+sec^2(t))(sec(t)+tan(t))^4$
Take the derivative of the equation using Trigonometric derivatives and Chain Rule: $s'=5\times(sec(t)+tan(t))^4\times(sec(t)tan(t)+sec^2(t))$ $=5(sec(t)tan(t)+sec^2(t))(sec(t)+tan(t))^4$