Answer
$x=-1.895, 0, 1.895$
Work Step by Step
Step 1. Let $f(x)=2sin(x)-x$, we have $f(-\pi/2)=2sin(-\pi/2)+\pi/2=-2+\pi/2\lt0$ and $f(\pi/2)=2sin(\pi/2)-\pi/2=2-\pi/2\gt0$
Step 2. Based on the Intermediate Value Theorem, there will be a zero between $x=-\pi/2$ and $x=\pi/2$; thus the equation will have at least one solution.
Step 3. Test more values: $f(-\pi)=2sin(-\pi)+\pi=\pi\gt0$ and $f(\pi)=2sin(\pi)-\pi=-\pi\lt0$
Step 4. Thus, there will be two more zeros in $(-\pi, -\pi/2)$ and $(\pi/2, \pi)$
Step 5. Graphing the function as shown, we can find three zero at $x=-1.895, 0, 1.895$
