Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 86: 75



Work Step by Step

Step 1. Let $f(x)=cos(x)-x$, we have $f(0)=cos(0)-0=1\gt0$ and $f(\pi/2)=cos(\pi/2)-\pi/2=-\pi/2\lt0$ Step 2. Based on the Intermediate Value Theorem, there will be a zero between $x=0$ and $x=\pi/2$. Step 3. Graphing the function as shown, we can find a zero at $x=0.739$
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