Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 86: 74

Answer

$3.516$
1575038054

Work Step by Step

Step 1. Let $f(x)=\sqrt x +\sqrt {1+x} -4$, we have $f(0)=0+1-4=-3\lt0$ and $f(4)=2+\sqrt 5-4=\sqrt 5-2\gt0$ Step 2. By using the Intermediate Value Theorem, we know that there is a zero between $x=0$ and $x=4$ Step 3. Graphing the function $f(x)$ as shown, we can find a solution at $x=3.516$
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