Answer
$x\approx-0.855,\ \ 0.403,$ and $1.452$
Work Step by Step
Note that
$f(0)=0-0-0+1=1$
$f(1)=2-2-2+1=-1$
Since the function is a polynomial, it is continuous everywhere.
$y_{0}=0$ is a value between $f(0)$ and $f(1)$.
The Intermediate Value theorem guarantees that there exists a $c\in(0,1)$ for which $f(c)=0$.
Graphing, we find that the roots are (approximately):
$x\approx-855,\ \ 0.403,$ and $1.452$
